Here we are going to see about the result and discussion, whether the solution to the given equation is correct or not. By simplifying the equation we find the value for the particular variable. when we substitute the value in the equation the equation balances on both sides.
For example: x – 4 = 0.
Here x – 4 = 0
Add 4 on both sides. We get
x = 4
The solution is x = 4
According to the topic we have to check whether x = 4 is a solution to the given equation or not. By substituting the value the in equation we can see that both sides have same value.
Example Problem for Result and Discussion Section:
Given equation is discussion section x + 7x + 5x + 3x – 5 + x = 29
Solution:
Given question is x + 7x + 5x + 3x – 5 + x = 29
Step 1:
Arrange the given question as per the x term and the numbers
x+ x + 3x + 5x + 7x – 5 = 29
Step 2:
Add the x term first
2x + 3x + 5x + 7x – 5 = 29
Step 3:
Add all the ' x ' term in the equation
17x – 5 = 29
Step 4:
Add both sides by 5.Then we get
17x = 29 + 5
Step 5:
17 x = 34
Divide by 17 on both sides.
`(17x)/17` = `34/17`
x = 2
Discussion section about the result:
The result is 2. Here we are going to discuss about the result for given equation, whether the solution x =2 is correct or not.
Given question is x + 7x + 5x + 3x – 5 + x = 29
The result is x =2
Here we need to substitute the x value in the equation if that both side value is equal means the solution is correct. Otherwise the solution is not correct.
x + 7x + 5x + 3x – 5 + x = 29
Substitute the value x = 2 in the given equation
2 + 7( 2) + 5( 2) + 3(2) – 5 + 2 = 29
2 + 14 + 10 + 6 – 5 + 2 = 29
34 – 5 = 29
29 = 29
Both the sides are equal, so given solution is correct for the equation.
One more Example Problem for Result and Discussion Section:
Solve discussion section 16x - 12 = 20
Solution:
Add 12 on both sides. we get
16x - 12 + 12 = 20 + 12
16x = 32
Divide by 16 on both sides.
`(16x )/ 16` = `32 / 16`
x = 2
whe we substitute x =2 in the equation 16x - 12 = 20. we get
16(2) - 12 = 20
32 - 12 = 20
20 = 20.
Thus the equation satisfies.
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